Raoult's law becomes a special case of Henry's law when

K_H > p₁⁰

No worries! We‘ve got your back. Try BYJU‘S free classes today!

K_H < p₁⁰

No worries! We‘ve got your back. Try BYJU‘S free classes today!

K_H = p₁⁰

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

^{all of the above}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C
K_H = p₁⁰

Raoult's law becomes a special case of Henry's law when K_Hbecomes equal to p₁⁰ in Henry's law.

Suggest Corrections

Similar questions

$p + 1$ is a factor of $p^{10} - 1$ .

p, q, r, s, t

x^{5} - 1 = 0

p^{10} + q^{10} + r^{10} + s^{10} + t^{10} =

P = K_{H} \times x

K_{H}

K_{H} -

p - 1

p^{10} - 1

p^{11} - 1

Join BYJU'S Learning Program