Rate constant for a n th order reaction has the dimensionsWhere M is concentration unitA- time -1 M 1-nB- time 1- n M -1C- time 1 M 1- n D- time -1 M 1- n

The correct option is A time^ 1 M^(1 n)Rate = k[conc]^n [conc]/time=k[conc]^n k = [conc]^1 n . time^ 1 = time^ 1 . M^1 n ...

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Byju's Answer

Standard XII

Chemistry

Order of Reaction

Rate constant...

Question

Rate constant for a $n^{t h}$ order reaction has the dimensions
(Where M is concentration unit)

t i m e^{- 1} M^{(1 - n)}

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t i m e^{1 - n} M^{- 1}

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t i m e^{1} M^{(1 - n)}

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t i m e^{- 1} M^{1 + n}

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Solution

The correct option is A $t i m e^{- 1} M^{(1 - n)}$
$R a t e = k [c o n c]^{n} \frac{[c o n c]}{t i m e} = k [c o n c]^{n} k = [c o n c]^{1 - n} . t i m e^{- 1} = t i m e^{- 1} . M^{1 - n}$

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Similar questions

Q. Rate constant for

n^{t h}

order reaction has dimensions:
(Where M is concentration units)

Q. Rate constant for a

n^{t h}

order reaction has the dimensions
(Where M is concentration unit)

If the mean of $x_{1}$ and $x_{2}$ is $M_{1}$ and that of $x_{1}, x_{2}, x_{3}, x_{4}$ is $M_{2}$ , then the mean of $a x_{1}, a x_{2}, \frac{x_{3}}{a}, \frac{x_{4}}{a}$ is

Q. If the mean of

x_{1}

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x_{2}

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and that of

x_{1}, x_{2}, x_{3}, x_{4}

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Q. Which is the correct expression for integrated rate law of

n^{t h}

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A \to Product(s)

Here,

a

is initial concentration of the reactant

x

is concentration of reactant consumed at time ‘t’

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Rate constant for a nth order reaction has the dimensions (Where M is concentration unit)

The correct option is A time−1M(1−n)Rate=k[conc]n[conc]time=k[conc]nk=[conc]1−n.time−1=time−1.M1−n

Rate constant for a $n^{t h}$ order reaction has the dimensions
(Where M is concentration unit)

The correct option is A $t i m e^{- 1} M^{(1 - n)}$
$R a t e = k [c o n c]^{n} \frac{[c o n c]}{t i m e} = k [c o n c]^{n} k = [c o n c]^{1 - n} . t i m e^{- 1} = t i m e^{- 1} . M^{1 - n}$