Rate constant for a reaction $H_{2} + I_{2} ⇌ 2 H I$ is 49, then rate constant for reaction $2 H I ⇌ H_{2} + I_{2}$ is :

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1/49

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Solution

The correct option is B 1/49
For reversible reaction rate constant is also reverse.
If k is the rate constant for the reaction $H_{2} + I_{2} ⇌ 2 H I$ and k' is the rate constant for the recation $2 H I ⇌ H_{2} + I_{2}$ ,

then $k^{'} = \frac{1}{k} = \frac{1}{49} .$

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