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Question

Rate constant for the decomposition of ethylene oxide into CH4 and CO may be described by the equation, log[k(s1)]=14.341.25×104T.
(a) What is the energy of activation of this reaction?
(b) What is the value of k at 670 K?

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Solution

(a) We know that,
log10k=log10AE2.303RT ...(i)
log10k(s1)=14.341.25×104T ...(ii)
Comparing equation (i) and equation (ii), we get
E2.303R=1.25×104
E=1.25×104×2.303×8.314×103
E=239.339kJ/mol
(b) Substituting the value of T, i.e., 670 K, in equation ?(ii), we get,
logk(s1)=14.341.25×104670=4.3167
k=4.82×105s1

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