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Question

Rate constant k of a reaction varies with temperature according to the equation logk=constantEa2.303R×1T where Ea is the energy of activation for the reaction. When a graph is plotted for logk vs 1T a straight line with a slope 6670k is obtained. The activation energy for this reaction will be:

(R=8.314JK1mol1)

A
122.65 kJmol1
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B
127.71 kJmol1
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C
142.34 kJmol1
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D
150.00 kJmol1
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