Question

Rate constant K varies with temperature by equation $\log K\left({min}^{-1}\right)=\log 5-\frac{2000Kcal}{RTX2.303}$ we can conclude that?

• A. Pre-exponential factor A is ${10}^5$
• B. $E_a$ IS $2000Kcal$
• C. $E_a$ is $9.12Kcal$
• D. The pre-exponential factor A is $5$

Answer 1

Answer: (A)

Pre-exponential factor A is ${10}^5$

Arrhenius equation gives the dependence of the rate constant of a chemical reaction on the absolute temperature, a pre-exponential factor and other constants of the reaction. where. k is the rate constant, T is the absolute temperature (in kelvins), A is the pre-exponential factor

$logK$ $=$ $logA$ $-$$\frac{E_a}{2.303RT}$ .....................$\left(1\right)$

Given equation:

$\log K\left({min}^{-1}\right)=\log 5-\frac{2000Kcal}{RTX2.303}$ .....................$\left(2\right)$

So, if we compare these two equations , then $logA$ $=$ $log5$

Pre-exponential factor, $A$ $=$ ${10}^5$