Rate constant of a reaction is $175 l i t r e^{2} m o l^{- 2} s e c^{- 1}$ . What is the order of reaction?

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Solution

We know that,
$Unit of rate constant (k) = {[\frac{l i t r e}{m o l}]}^{n - 1} \times s e c^{- 1} \cdot \cdot \cdot (i)$
$Given unit of rate constant k = l i t r e^{2} m o l^{- 2} s e c^{- 1} \cdot \cdot \cdot (i i)$
Comparing the unit of litre,
$n - 1 = 2$
$\Rightarrow n = 3$

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