Rate law for the reaction, $A + 2 B \to C$ is found to be, $R a t e = k [A] [B]$

The concentration of reactant $^{'} B^{'}$ is doubled, keeping the concentration of $^{'} A^{'}$ constant, the value of the rate constant will be:

the same

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doubled

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quadrupled

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halved

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Solution

The correct option is A the same
The rate constant of a reaction does not depend upon concentrations of the reactants. Thus, it will remain the same. The rate constant of a reaction depends on temperature not on concentration.

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Q. Rate law for the reaction,

A + 2 B \to C

is found to be

R a t e = k [A] [B]

Concentration of reactant 'B' is doubled, keeping the concentration of 'A' constant, the value of rate constant will be ................. .

In a reaction, $A + B \to$ Product, rate is doubled when the concentration of B is doubled and rate increases by a factor of 8 when the concentrations of both the reactants (A and B) are doubled. Rate law for the reaction can be written as :

Q. For the reaction:

A + B \to C + D

, doubling the concentration of both the reactants increases the reaction rate by 8 times and doubling the concentration of only B simply doubles the reaction rate. The rate law is given as:

Q. For the reaction A + B

\to

C + D, doubling the concentration of both the reactants increases the reaction rate by 8 times and doubling the initial concentration of the only B simply doubles the reaction rate. The rate law for the reaction is:

A + 2 B \to C

, the rate equation for reaction is given as

R a t e = [A] [B]

. If the concentration of A is kept constant while B is doubled. What will happen to the rate?

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Rate law for the reaction, A+2B→C is found to be, Rate=k[A][B]The concentration of reactant ′B′ is doubled, keeping the concentration of ′A′ constant, the value of the rate constant will be:

The correct option is A the sameThe rate constant of a reaction does not depend upon concentrations of the reactants. Thus, it will remain the same. The rate constant of a reaction depends on temperature not on concentration.

Rate law for the reaction, $A + 2 B \to C$ is found to be, $R a t e = k [A] [B]$

The concentration of reactant $^{'} B^{'}$ is doubled, keeping the concentration of $^{'} A^{'}$ constant, the value of the rate constant will be:

The correct option is A the same
The rate constant of a reaction does not depend upon concentrations of the reactants. Thus, it will remain the same. The rate constant of a reaction depends on temperature not on concentration.