Rate of change of sinx with respect to cosx at x=π2will be ___
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Solution
What do you understand by rate of change of sinx with respect to cos x?
Isn’t it d(sinx)d(cosx)
i.e., derivative of sinx with respect to cosx =d(sinx)d(cosx) =(ddx(sinx))(ddx(cosx))=cosx−sinx=−cotx.
At x=π2,cotx=0, which is the correct answer.