Rate of change of weight near the earth's surface varies with height (h) as

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h⁰

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h^-1

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h^1/2

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Solution

The correct option is B
h⁰

$g_{h}$ =g (1 - $\frac{2 h}{R}$ ) (h << R, radius of earth)

Rate of change of weight with feight ,

= | $\frac{d w}{d h}$ | = | $\frac{d (m g)}{d h}$ | = m| $\frac{d (g)}{d h}$ |

=| $\frac{2 m g}{R}$ | = constant

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Rate of change of weight near the earth's surface varies with height h (h<<R where R is the radius of the Earth) as

60^{\circ}

g = 10 {m/s}^{2}

60^{\circ}

g = 10 {m/s}^{2}

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