Rate of diffusion of a gas is 720 $m l / m i n$ . But the gas diffused for 20 seconds only. The volume of the gas diffused in $m l$ is:

240

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Solution

The correct option is C 240
Solution:-
Rate of diffusion of gas in $720 m l / m i n$ , i.e.

The volume of gas diffused in 60 seconds (1 min) $= 720 m L$

$∴$ Volume of gas diffused in 20 seconds $= \frac{720}{60} \times 20 = 240 m L$

Hence, $240 m L$ of gas diffused in 20 seconds.

Option A is correct.

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Rate of diffusion of a gas is 720 ml/min. But the gas diffused for 20 seconds only. The volume of the gas diffused in ml is:

The correct option is C 240Solution:-Rate of diffusion of gas in 720 ml/min, i.e.The volume of gas diffused in 60 seconds (1 min) =720 mL∴ Volume of gas diffused in 20 seconds =72060×20=240 mLHence, 240 mL of gas diffused in 20 seconds.Option A is correct.

Rate of diffusion of a gas is 720 $m l / m i n$ . But the gas diffused for 20 seconds only. The volume of the gas diffused in $m l$ is: