Rate of diffusion of gas $X$ is 1/4th of rate of diffusion of gas $Y$ . Identify $X$ and $Y$ :

S O_{2}, C H_{4}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C H_{4}, H_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

S O_{2}, H e

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

H_{2}, O_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $S O_{2}, H e$
Ratio of rates of diffusion of gases is given as; $\frac{R_{1}}{R_{2}} = \sqrt{\frac{M_{2}}{M_{1}}}$
Therefore $X$ = $S O_{2}$ and $Y$ = $H e$ as $\sqrt{\frac{M_{2}}{M_{1}}}$ = $\sqrt{\frac{64}{4}} = 4 : 1$ where $M_{2}$ = $S O_{2}$ and $M_{1}$ = $H e$

Suggest Corrections

Similar questions

S O_{2}

O_{2}

C H_{4}

The ratio fo rates of diffusion of $S O_{2}, O_{2} a n d C H_{4}$ is

N_{2}, O_{2}

S O_{2}

The ratio of rates of diffusion of $S O_{2}, O_{2} a n d C H_{4}$ is .....

The ratio fo rates of diffusion of $S O_{2}, O_{2} a n d C H_{4}$ is

Join BYJU'S Learning Program