Question

Rate of effusion of an ozonised sample is 0.95 times rate of effusion of pure oxygen . Mass% of ozone in ozonised sample is ?

Answer 1

We realize that dissemination rate is conversely relative to the square foundation of the molar masses.
If so, ozonized gas diffuses slower than O2 then it has higher molar mass since ozone is O3
The molar weight of ozonized gas =(32g/mole)/(0.95)
=33.68g/mol
The blend contains O2 with molar mass 32g/mole and Ozone with molar mass of 48g/mole
So let X be the mole portion of O2 and 1-X be the mole division of Ozone.
Hence,
X*32g/mole +(1-X)*48g/mole =33.68g/mole
32x+48-48x=33.68
-16x+48=33.68
-16x= -14.32
or
X=14.32/16
Rate of ozone;
=(1-X)*100
=(1-14.32/16)*100
= .105*100=10.5
Ozone =10%