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Question

Rate of formation of SO3 in the following reaction 2SO2+O22SO3 is 100 g min1. Hence, rate of disappearance of O2 is:

A
50 g min1
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B
40 g min1
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C
200 g min1
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D
25 g min1
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Solution

The correct option is A 50 g min1

For the reaction:2SO2+O22SO3

The rate in terms of reactants is given as negative as the concentration of reactants is decreasing with time whereas the rate in terms of products is given as positive as the concentration of products is increasing with time.

Rate=1d[SO2]2dt=d[O2]dt=+1d[SO3]2dt

Given. +1d[SO3]dt=100 g/min

d[O2]dt=+1d[SO3]2dt

d[O2]dt=12×100 g/min

d[O2]dt=50 g/min

Thus, option A is correct.


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