CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
418
You visited us 418 times! Enjoying our articles? Unlock Full Access!
Question

Rate of formation of SO3 in the following reaction 2SO2+O22SO3 is 100 g min1. Hence, rate of disappearance of O2 is:

A
50 g min1
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
40 g min1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
200 g min1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
25 g min1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 50 g min1

For the reaction:2SO2+O22SO3

The rate in terms of reactants is given as negative as the concentration of reactants is decreasing with time whereas the rate in terms of products is given as positive as the concentration of products is increasing with time.

Rate=1d[SO2]2dt=d[O2]dt=+1d[SO3]2dt

Given. +1d[SO3]dt=100 g/min

d[O2]dt=+1d[SO3]2dt

d[O2]dt=12×100 g/min

d[O2]dt=50 g/min

Thus, option A is correct.


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Factors Affecting Rate of a Chemical Reaction
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon