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Question

Rate of increment of energy in an inductor with time, in series LR circuit getting charge with battery of e.m.f. E is best represented by [inductor has initially zero current]-

A
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B
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C
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D
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Solution

The correct option is A
Rate of increment of energy in indcutor
=dUdt=ddt[12Li2]=Lididt
Current in the inductor at time t is:
i=i0(1etτ) and didt=i0τetτ
dUdt=Li20τetτ(1etτ)
dUdt=0 at t = 0 and t=
Hence, E is best represented by (A).

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