Question

Ratio between ages of A and B is 3 : 4 and ratio between ages of A and C is 4 : 5. If age of B is 3 years more than that of C then find sum of their ages .
Sol.

Answer 1

Ratio between ages of A and B$=3:4$

Let constant here be $x$

Then , age of A$=3x$ and age of B$=4x$

Ratio between ages of A and C$=4:5$

Let constant here be $y$

Then , age of A$=4y$ and age of C$=5y$

Then According to question,

$4x=5y+3$ ..................1

Also, $3x=4y$ .................2

Solving eq. 1 and 2 we get ,

$x=12$ and $y=9$

Hence age of A=36 years,age of B=48 years and age of C=45 years

Then sum of ages of B and C$=48+45=93years$