Question

Ratio in which the point (8,7) divides the line segment joining the points $(\frac{28}{3},\frac{22}{3})and(\frac{20}{3},\frac{20}{3})$ is k:1. k =.

• A. 0.0
• B. 1
• C. 2
• D. 3

Answer 1

The correct option is B 1

Let the point, say C(8, 7) divides the line segment joining the points
$(\frac{28}{3},\frac{22}{3})\text{and}(\frac{20}{3},\frac{20}{3})$ in the ratio of k : 1. Then,
$\frac{(k\times \frac{20}{3}+\frac{28}{3})}{(k+1)}=8\Rightarrow k\times \frac{20}{3}+\frac{28}{3}=8k+8\Rightarrow k=1$
Hence the point (8, 7) divides the line segment joining the points $(\frac{28}{3},\frac{22}{3})\text{and}(\frac{20}{3},\frac{20}{3})$ in the ratio 1 : 1.