Question

Ratio of amplitude of two waves is 1 : 16. The ratio of maximum to minimum intensity when 2 waves interfere is:

• A. $289:25$
• B. $1:256$
• C. $289:225$
• D. $3:1$

Answer 1

The correct option is C $289:225$

$\frac{A_1}{A_2}=\frac{1}{16}$

$\frac{MaximumIntensity}{MinimumIntensity}=\frac{(A_1+A_2{)}^2}{(A_1-A_2{)}^2}=\frac{(1+16{)}^2}{(1-16{)}^2}$

$=\frac{(17{)}^2}{(15{)}^2}=\frac{289}{225}=289:225\left(C\right)$