Question

Ratio of area of hole to beaker is $0.1$. Height of liquid in beaker is $3m$, and hole is at the height of $52.5cm$ from the bottom of beaker, find the square of the velocity of liquid coming out from the hole

• A. $50{\left(m/s\right)}^2$
• B. $50.5{\left(m/s\right)}^2$
• C. $51{\left(m/s\right)}^2$
• D. $42{\left(m/s\right)}^2$

Answer 1

The correct option is A $50{\left(m/s\right)}^2$

$u^2=\frac{2gh}{[1-{\left(\frac{A_0}{A}\right)}^2]}=50{\left(m/s\right)}^2$