Question

Ratio of $s{p}^3$ and $s{p}^2$ hybridized atoms in the anionic part of Borax is ( if ans is 12 : 4 then represent as 124 ):

• A. $0112$
• B. $1201$
• C. $1121$
• D. $1321$

Answer 1

The correct option is A $0112$

Anionic part of borax => ${\left[B_4{O}_5{\left(OH\right)}_4\right]}^{2-}$

No. of ${sp}^3$ hybridized atom$=11$

No. of ${sp}^2$ hybridized atom $=2$

Ratio => $11:2$

Answer => $0112$