Question

Ratio of equivalent resistance between terminals A and B to terminals C and D i.e. $\frac{R_{AB}}{R_{CD}}$

Answer 1

$R_{AB}=\frac{10\times 8}{10+8}=\frac{80}{18}\dots \dots \dots \left(1\right)$
$R_{CD}=10\dots \dots \dots \left(2\right)$