CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

Ratio of income of $$A$$ and $$B$$ is $$6 : 5$$ ratio of their expenditure is $$3 : 2$$, if $$A$$ saves $$\dfrac  {1}{4}^{(th)}$$ of his income , find ratio of their monthly savings?


A
1:2
loader
B
2:3
loader
C
3:4
loader
D
4:5
loader

Solution

The correct option is C $$3:4$$
Let the income of $$A=6x$$
Let the income of $$B=5x$$
Let the expenditure of $$A=3y$$
Let the expenditure of $$B=2y$$
Therefore , savings of $$A=6x-3y$$
Savings of $$B=5x-2y$$
Now, as $$A$$ saves $$\cfrac{1}{4}^{th}$$ of his income,
$$6x-3y=\cfrac{1}{4}(6x)$$
$$24x-12y=6x$$
$$18x=12y$$
$$3x=2y$$
Now, ratio of savings of $$A$$ and $$B$$ $$=\cfrac{6x-3y}{5x-2y}$$
$$=\cfrac{6x-\left(\cfrac{3}{2}x\right)\times 3}{5x-3x}=\cfrac{3}{4}=3:4$$


Maths

Suggest Corrections
thumbs-up
 
0


similar_icon
Similar questions
View More


similar_icon
People also searched for
View More



footer-image