Ratio of sum of n terms of two distinct AP is 7n-1 3n-1 then

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Sum of 'n' Terms of an Arithmetic Progression

Ratio of sum ...

Question

Ratio of sum of n terms of two distinct AP is $\frac{7 n + 1}{3 n - 1}$ then

Ratio of there 6th term =39/16

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Ratio of there 1th term =4

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Ratio of there 5th term =2

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None of these

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The ratio between the sum of n terms of two A.P.'s is (7n+1):(4n+27). Find the ratio of their 11th terms.

n

(7 n + 1) : (4 n + 27)

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