Ratio of the radii of two Bohr orbits of H-atom is 4- 1- what would be the nomenclature-options are below1- K - L2- L - K3- N - L4- 283 BOTHThe answer given is 4 th optionBt I think it may be 2 nd option-

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Ratio of the radii of two Bohr orbits of H-atom is 4:1.what would be the nomenclature.options are below

1. K & L

2. L & K

3. N & L

4. 2&3 BOTH

The answer given is 4th option

Bt I think it may be 2nd option.

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Solution

4th Option is the correct one

R= .529 *(n^2/Z )

R is directly proportional to n^2

n = no. Of orbit

Z =atomic no.

Given R1/R2 = 4:1

n1 ^2/n2^ 2 = 4:1

n1/n2 = 2:1

Among 1st 4 orbits

n1 = 4 or 2 (n1^2 could be 16 and then n2^2 could be 4 and the ratio would be 4:1, So we are considering both n1 as 4 and 2 )

n2 =2 or 1

n1 could be either 4 or 2

If n1 = 4 then n2 =2, The shells are n1 = N and n2 = L

Or n1= 2 then n2 = 1, The shells are n1 = L and n2 = K

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Ratio of the radii of two Bohr orbits of H-atom is 4:1.what would be the nomenclature.options are below 1. K & L 2. L & K 3. N & L 4. 2&3 BOTH The answer given is 4th option Bt I think it may be 2nd option.

Ratio of the radii of two Bohr orbits of H-atom is 4:1.what would be the nomenclature.options are below

1. K & L

2. L & K

3. N & L

4. 2&3 BOTH

The answer given is 4th option

Bt I think it may be 2nd option.