Rational numbers are commutative under .........

subtraction

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multiplication

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division

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none of these

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Solution

The correct option is B multiplication
For any two rational numbers $a$ and $b, a \times b = b \times a$ . Thus, multiplication is commutative for rational numbers.

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Similar questions

Q. Rational numbers are commutative under

Q. (i) Are rational numbers always closed under division?
(ii) Are rational numbers always commutative under division?
(iii) Are rational numbers always associative under division?
(iv) Can we divide 1 by 0?

Question 3
The numerical expression $\frac{3}{8} + \frac{(- 5)}{7} = \frac{- 19}{56}$ shows that:
(a) rational numbers are closed under addition.
(b) rational numbers are not closed under addition.
(c) rational numbers are closed under multiplication.
(d) addition of rational numbers is not commutative.

Q. Write 'T' for true and 'F' for false for each of the following:
(i) Rational numbers are always closed under subtraction.
(ii) Rational numbers are aways closed under division.
(iii) 1 ÷ 0 = 0.
(iv) Subtraction is commutative on rational numbers.
(v)

- (\frac{- 7}{8}) = \frac{7}{8} .

Question 5
$- \frac{3}{8} + \frac{1}{7} = \frac{1}{7} + (\frac{- 3}{8})$ is an example to show that
(a) addition of rational numbers is commutative.
(b) rational numbers are closed under addition.
(c) addition of rational number is associative.
(d) rational numbers are distributive under addition

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Rational numbers are commutative under .........

The correct option is B multiplicationFor any two rational numbers a and b,a×b=b×a. Thus, multiplication is commutative for rational numbers.

The correct option is B multiplication
For any two rational numbers $a$ and $b, a \times b = b \times a$ . Thus, multiplication is commutative for rational numbers.