Question

Rational the denominator: $\frac{6-4\sqrt{3}}{6+4\sqrt{3}}$

Answer 1

On rationalising , we get

$\frac{6-4\sqrt{3}}{6+4\sqrt{3}}\times \frac{6-4\sqrt{3}}{6-4\sqrt{3}}$

$⟹\frac{(6-4\sqrt{3}{)}^2}{36-32}$
$⟹\frac{36+48-48\sqrt{3}}{36-48}$

$⟹\frac{84-48\sqrt{3}}{-12}$

$⟹4\sqrt{3}-7$