Rationalizing the denominator of √3+12√2−√3.
√3+12√2−√3×(2√2+√3)(2√2+√3)
=(√3+1)(2√2+√3)(2√2)2−(√3)2
=2√6+3+2√2+√38−3
=2(√6+√2)+√3+35