Rationalise- -2 -3-2 - -3

The correct option is D (5+2√(6)) √(2) +√(3)√(2) √(3)×√(2) +√(3)√(2) + √(3)=2+3+2√(2)√(3)2 3= 5+2√(6)1 ...

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Byju's Answer

Standard IX

Mathematics

Rationalisation

Rationalise: ...

Question

Rationalise:
$\frac{\sqrt{2} + \sqrt{3}}{\sqrt{2} - \sqrt{3}}$

5 + 2 \sqrt{6}

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- (5 + 2 \sqrt{6})

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5 - 2 \sqrt{6}

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- (5 - 2 \sqrt{6})

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Solution

The correct option is D $- (5 + 2 \sqrt{6})$
$\frac{\sqrt{2} + \sqrt{3}}{\sqrt{2} - \sqrt{3}} \times \frac{\sqrt{2} + \sqrt{3}}{\sqrt{2} + \sqrt{3}} = \frac{2 + 3 + 2 \sqrt{2} \sqrt{3}}{2 - 3} = - \frac{5 + 2 \sqrt{6}}{1}$

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Similar questions

Q. Rationalise the denominator and simplify

\frac{2 \sqrt{6} - \sqrt{5}}{3 \sqrt{5} - 2 \sqrt{6}}

Q. Rationalise the denominator and simplify

\frac{\sqrt{5}}{\sqrt{6} + 2} - \frac{\sqrt{5}}{\sqrt{6} - 2}

Rationalise the denominator and simplify

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(5)

(6)

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(13)

Question 6

Which of the following expressions show that rational numbers are associative under multiplication.
(a) $\frac{2}{3} \times (\frac{- 6}{7} \times \frac{3}{5}) = (\frac{2}{3} \times \frac{- 6}{7}) \times \frac{3}{5}$
(b) $\frac{2}{3} \times (\frac{- 6}{7} \times \frac{3}{5}) = \frac{2}{3} \times (\frac{3}{5} \times \frac{- 6}{7})$
(c) $\frac{2}{3} \times (\frac{- 6}{7} \times \frac{3}{5}) = (\frac{3}{5} \times \frac{2}{3}) \times \frac{- 6}{7}$
(d) $(\frac{2}{3} \times \frac{- 6}{7}) \times \frac{3}{5} = (\frac{- 6}{7} \times \frac{2}{3}) \times \frac{3}{5}$

Question 6

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Rationalise:√2+√3√2−√3

The correct option is D −(5+2√6)√2+√3√2−√3×√2+√3√2+√3=2+3+2√2√32−3=−5+2√61

Rationalise:
$\frac{\sqrt{2} + \sqrt{3}}{\sqrt{2} - \sqrt{3}}$

The correct option is D $- (5 + 2 \sqrt{6})$
$\frac{\sqrt{2} + \sqrt{3}}{\sqrt{2} - \sqrt{3}} \times \frac{\sqrt{2} + \sqrt{3}}{\sqrt{2} + \sqrt{3}} = \frac{2 + 3 + 2 \sqrt{2} \sqrt{3}}{2 - 3} = - \frac{5 + 2 \sqrt{6}}{1}$