Question

Rationalise the denominator$\frac{\sqrt{3}-\sqrt{2}}{\sqrt{3}+\sqrt{2}}$

Answer 1

$\frac{\sqrt{3}-\sqrt{2}}{\sqrt{3}+\sqrt{2}}$

$=\frac{\left(\sqrt{3}-\sqrt{2}\right)\left(\sqrt{3}-\sqrt{2}\right)}{\left(\sqrt{3}+\sqrt{2}\right)\left(\sqrt{3}-\sqrt{2}\right)}$

$=\frac{3+2-2\sqrt{6}}{3-2}$

$=5-2\sqrt{6}$