1
You visited us
1
times! Enjoying our articles?
Unlock Full Access!
Byju's Answer
Standard X
Mathematics
Quadratic Formula
Rationalise t...
Question
Rationalise the denominator:
√
a
+
x
+
√
a
−
x
√
a
+
x
−
√
a
−
x
.
A
a
−
√
a
2
−
x
2
x
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
a
+
√
a
2
+
x
2
x
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
a
−
√
a
2
+
x
2
x
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
a
+
√
a
2
−
x
2
x
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution
The correct option is
C
a
+
√
a
2
−
x
2
x
√
a
+
x
+
√
a
−
x
√
a
+
x
−
√
a
−
x
=
√
a
+
x
+
√
a
−
x
√
a
+
x
−
√
a
−
x
×
√
a
+
x
+
√
a
−
x
√
a
+
x
+
√
a
−
x
=
(
√
a
+
x
+
√
a
−
x
)
2
(
√
a
+
x
)
2
−
(
√
a
−
x
)
2
=
a
+
x
+
a
−
x
+
(
2
√
a
+
x
√
a
−
x
)
(
a
+
x
)
−
(
a
−
x
)
=
2
a
+
(
2
√
a
2
−
x
2
)
2
x
=
a
+
(
√
a
2
−
x
2
)
x
Suggest Corrections
0
Similar questions
Q.
How many of the following integrals are correct?
1.
∫
d
x
√
x
2
+
a
2
=
l
n
|
x
+
√
x
2
+
a
2
|
+
C
2.
∫
d
x
√
x
2
−
a
2
=
l
n
|
x
−
√
x
2
−
a
2
|
+
C
3.
∫
d
x
x
2
−
a
2
=
1
2
a
l
n
∣
∣
x
−
a
x
+
a
∣
∣
+
C
4.
∫
d
x
a
2
−
x
2
=
1
2
a
l
n
∣
∣
x
+
a
x
−
a
∣
∣
+
C
___
Q.
Show that
∫
x
√
a
2
−
x
2
a
2
+
x
2
d
x
=
√
a
2
−
x
2
−
a
√
(
2
)
log
a
√
2
+
√
a
2
−
x
2
a
√
(
2
)
−
√
(
a
2
−
x
2
)
.
Q.
Find the limits of
√
a
2
+
a
x
+
x
2
−
√
a
2
−
a
x
+
x
2
√
a
+
x
−
√
a
−
x
,
when
x
=
0
.
Q.
l
i
m
x
→
0
√
a
2
−
a
x
+
x
2
−
√
a
2
+
a
x
+
x
2
√
a
+
x
−
√
a
−
x
is equal to (a > 0)
Q.
lim
x
→
0
f
(
x
)
, where
f
(
x
)
=
√
a
2
−
a
x
+
x
2
−
√
a
2
+
a
x
+
x
2
√
a
+
x
−
√
a
−
x
is
View More
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
Related Videos
Solving QE using Quadratic Formula
MATHEMATICS
Watch in App
Explore more
Quadratic Formula
Standard X Mathematics
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
AI Tutor
Textbooks
Question Papers
Install app