Question

Rationalise the denominator $\frac{3-\sqrt{2}}{3+\sqrt{2}}$.

Answer 1

$\frac{3-\sqrt{2}}{3+\sqrt{2}}=\frac{3-\sqrt{2}}{3+\sqrt{2}}\times \frac{3-\sqrt{2}}{3-\sqrt{2}}$

$=\frac{9+2-6\sqrt{2}}{7}$

$=\frac{11-6\sqrt{2}}{7}$