Rationalise the denominator(i) 222√3+1
Simplify:
(i) {(13)−3−(12)−3}÷(14)−3 (ii)(32−22)×(23)−3(iii) {(12)×(−4)−1}−1 (iv) [{(−14)2}−2]−1(v) {(23)2}3×(13)−4×3−1×6−1