Rationalisation of the denominator of 1√5+√2 gives
(a)1√10 (b)√5+√2 (c)√5−√2 (d)√5−√23
Rationalise the denominators of each of the following:
(i) 3√5
(ii) 32√5
(iii) 1√12
(iv) √2√5
(v) √3+1√2
(vi) √2+√5√3
(vii) 3√2√5