Question

Rationalise the denominator of $\frac{3\sqrt[3]{35}}{\sqrt[3]{39}}$

• A. $\sqrt[3]{315}$
• B. $\sqrt[3]{35}$
• C. $\sqrt[3]{325}$
• D. $\sqrt[3]{335}$

Answer 1

The correct option is A $\sqrt[3]{315}$

$\frac{3\sqrt[3]{35}}{\sqrt[3]{39}}$

$=\frac{3\sqrt[3]{35\times 3}}{\sqrt[3]{39\times 3}}$

$=\frac{3\sqrt[3]{315}}{3}$

$=\sqrt[3]{315}$