Rationalise the denominator of 1√3−√2.
√3+√2
√5+√2
√3−√2
√5+√3
Rationalising factor of 1√3−√2 is √3+√2 .
Multiplying both the numerator and denominator with √3+√2, we get
1√3−√2 × √3+√2√3+√2
= √3+√23−2
= √3+√2
Rationalise the denominator
√3_√2_1