Question

Rationalise the denominator of :
(i) $\frac{2}{\sqrt{3}}$

• A. $\frac{2\sqrt{3}}{4}$
• B. $\frac{2\sqrt{3}}{3}$
• C. $\frac{2\sqrt{3}}{9}$
• D. $\frac{2\sqrt{3}}{6}$

Answer 1

Answer: (B)

$\frac{2\sqrt{3}}{3}$

$\frac{2}{\sqrt{3}}$
Rationalizing the denominator , we get
$\frac{2\times \sqrt{3}}{\sqrt{3}\times \sqrt{3}}$
$=\frac{2\sqrt{3}}{3}$