Question

Rationalise the denominator of the following:
$\frac{2}{3\sqrt{3}}$

Answer 1

$\frac{2}{3\sqrt{3}}$

Dividing the numerator and denominator by $\sqrt{3}$

$=\frac{2\sqrt{3}}{3\sqrt{3}\sqrt{3}}$

$=\frac{2\sqrt{3}}{3\times 3}$

$=\frac{2\sqrt{3}}{9}$

Hence rationalized.