Rationalise the following denominator- 2-8-2-5-3-

The correct option is A 4√(2)(2√(5)+√(3))/17 #160; 2√(8)2√(5) √(3) #10; = 2√(8)2√(5) √(3)× #160;2√(5)+√(3)2√(5)+√(3) #10; = 4√(40)+2√ ...

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Rationalisation

Rationalise t...

Question

Rationalise the following denominator:
$\frac{2 \sqrt{8}}{2 \sqrt{5} - \sqrt{3}}$ .

\frac{4 \sqrt{2} (2 \sqrt{5} + \sqrt{3})}{37}

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\frac{4 \sqrt{2} (2 \sqrt{5} + \sqrt{3})}{17}

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\frac{4 \sqrt{2} (2 \sqrt{5} + \sqrt{3})}{27}

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\frac{4 \sqrt{2} (2 \sqrt{5} + \sqrt{3})}{7}

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Similar questions

\frac{22}{2 + \sqrt{3} + \sqrt{5}} .

{⎛ ⎝ \sqrt{{(\sqrt{5} - \frac{5}{2})}^{2}} - \sqrt[3]{{(\frac{3}{2} - \sqrt{5})}^{3}} ⎞ ⎠}^{1 / 2} - \sqrt{2} sin \frac{7 π}{4}

Solve:

(i) $2 - \frac{3}{5}$

(ii) $4 + \frac{7}{8}$

(iii) $\frac{3}{5} + \frac{2}{7}$

(iv) $\frac{9}{11} - \frac{4}{15}$

(v) $\frac{7}{10} + \frac{2}{5} + \frac{3}{2}$

(vi) $2 \frac{2}{3} + 3 \frac{1}{2}$

(vii) $8 \frac{1}{2} - 3 \frac{5}{8}$

\frac{4}{1!} + \frac{11}{2!} + \frac{22}{3!} + \frac{37}{4!} + \frac{56}{5!} + . . . \infty = b e - 1

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