Rationalize the denominator of 3-7-9

Rationalizing the expression, we get, 3 √(7) √(9)= 3√(7)+3= 33+√(7)= 33+√(7)×(3 √(7))(3 √(7))= 3(3 √(7))3^2 ( √(7))^2= 3(3 √(7))9 7= 3(3 √(7))2= 3(3 √(7))2 ...

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Byju's Answer

Standard X

Mathematics

Multiplication of Rational Expressions

Rationalize t...

Question

Rationalize the denominator of $\frac{3}{- \sqrt{7} - \sqrt{9}}$

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Solution

Rationalizing the expression, we get,
$\frac{3}{- \sqrt{7} - \sqrt{9}} = \frac{- 3}{\sqrt{7} + 3} = \frac{- 3}{3 + \sqrt{7}} = \frac{- 3}{3 + \sqrt{7}} \times \frac{(3 - \sqrt{7})}{(3 - \sqrt{7})} = \frac{- 3 (3 - \sqrt{7})}{3^{2} - (- \sqrt{7})^{2}} = \frac{- 3 (3 - \sqrt{7})}{9 - 7} = \frac{- 3 (3 - \sqrt{7})}{2} = \frac{- 3 (3 - \sqrt{7})}{2}$

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Rationalize the denominator of 3−√7−√9

Rationalizing the expression, we get, 3−√7−√9=−3√7+3=−33+√7=−33+√7×(3−√7)(3−√7)=−3(3−√7)32−(−√7)2=−3(3−√7)9−7=−3(3−√7)2=−3(3−√7)2

Rationalize the denominator of $\frac{3}{- \sqrt{7} - \sqrt{9}}$