Question

Rationalize the denominator of $\frac{3-\sqrt{2}}{3+\sqrt{2}}$.

Answer 1

$\frac{(3-\sqrt{2})}{3+\sqrt{2}}\frac{(3-\sqrt{2})}{3+\sqrt{2}}$

$\frac{(3-\sqrt{2}{)}^2}{9-2}\Rightarrow \frac{9+2-6\sqrt{2}}{7}$

$=\frac{11-6\sqrt{2}}{7}$