Question

Ravi and Ajay start simultaneously from a place $A$ towards place $B,$ $60$ km apart. Ravi's speed is $4$ km/hr less than that of Ajay. Ajay after reaching $B,$ turns back and meets Ravi at a place $12$ km away from $B.$ Ravi's speed is

• A. $12$ km/hr
• B. $10$ km/hr
• C. $8$ km/hr
• D. $6$ km/hr

Answer 1

The correct option is C $8$ km/hr

Let Ravi's speed be $x$ km/hr.
Then, Ajay's speed $=(x+4)$ km/hr.
Distance covered by Ajay $=60+12=72$ km
Distance covered by Ravi $=60-12=48$ km
According to question, we have
$\frac{72}{x+4}=\frac{48}{x}$
$\Rightarrow 3x=2x+8$
$\Rightarrow x=8$ km/hr
Hence, Ravi's speed $=8$ km/hr