Ravi had 5-6 th of a cake with him- He ate 2-3 rd of it- The total amount of cake eaten by him is-

The correct option is A 5/9Part of the cake eaten by Ravi =2/3 of nbsp;5/6 = nbsp;2/3×5/6 = nbsp;10/18 = nbsp;5/9 ...

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Byju's Answer

Standard V

Mathematics

Addition & Subtraction of Decimals

Ravi had 5/6 ...

Question

Ravi had ${\frac{5}{6}}^{th}$ of a cake with him. He ate ${\frac{2}{3}}^{rd}$ of it. The total amount of cake eaten by him is.

\frac{5}{9}

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\frac{10}{12}

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\frac{10}{6}

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\frac{10}{3}

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Solution

The correct option is A $\frac{5}{9}$
Part of the cake eaten by Ravi
$= \frac{2}{3} of \frac{5}{6} = \frac{2}{3} \times \frac{5}{6} = \frac{10}{18} = \frac{5}{9}$

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Ravi had 56th of a cake with him. He ate 23rd of it. The total amount of cake eaten by him is.

The correct option is A 59Part of the cake eaten by Ravi =23 of 56=23×56=1018=59

Ravi had ${\frac{5}{6}}^{th}$ of a cake with him. He ate ${\frac{2}{3}}^{rd}$ of it. The total amount of cake eaten by him is.

The correct option is A $\frac{5}{9}$
Part of the cake eaten by Ravi
$= \frac{2}{3} of \frac{5}{6} = \frac{2}{3} \times \frac{5}{6} = \frac{10}{18} = \frac{5}{9}$