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Question
Ravi's father bought two houses: one for Rs.12,56,000andtheotherforRs. 23,48,000$. How much did he spend altogether? By how much was the second house more expensive than the first?
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Solution
Ravi’s father bought first house for Rs12,56,000
and he bought second house for Rs23,48,000.
The total money used will be,
Rs12,56,000+Rs23,48,000=Rs36,04,000
The difference between the both costs is,
Rs23,48,000−Rs12,56,000=Rs10,92,000
Therefore, the second house is Rs10,92,000
expensive than the first house.
Ravi’s father bought first house for Rs12,56,000 and he bought second house for Rs23,48,000.
The total money used will be,
Rs12,56,000+Rs23,48,000=Rs36,04,000
The difference between the both costs is,
Rs23,48,000−Rs12,56,000=Rs10,92,000
Therefore, the second house is Rs10,92,000 expensive than the first house.
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