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Question

Ravish wanted to make a temporary shelter for his car by making a box-like structure with tarpaulin that covers all the four sides and the top of the car (with the front face as a flap which can be rolled up). How much tarpaulin would be required to make the shelter if height is 2.5 m and dimensions of the base are 4 m×3 m?


A

37 m2

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B

47 m2

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C

30 m2

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D

54 m2

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Solution

The correct option is B

47 m2


Length of base (l) = 4 m

Breadth (b) = 3 m

Height (h) = 2.5 m

Area of tarpaulin used

=Area of four walls+Area of the roof

[Area of four walls = LSA of this cuboid-shaped shelter]

=[2h(l+b)]+[l×b]

=[2×2.5(4+3)]+[4×3]

=[5×7]+12

=35+12

=47 m2


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