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Question

Ray PQ and ray PR are perpendicular to each other. Points B and A are in the interior and exterior of QPR respectively. Ray PB and ray PA are perpendicular to each other. Draw a figure all this rays and write-A pair of complementary angles A pair of supplementary anglesA pair of congruent angles.

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Solution


Ray PQ and PRare perpendicular each other. Point B is the interior and Point A is the exterior of QPR.
Ray PB and PA are perpendicular to each other.
(i) A pair of Complementary angles:
QPB and BPR because their sum is 90o
BPR and RPA because their sum is 90o
(ii) A pair of Supplementary angles:
QPR and BPA because their sum is 180o
(iii) A pair of congruent angles:
BPAQPR [ Each angle is 90o ]
BPA=QPR
So, RPA+BPR=BPR+QPB [ Using angle addition property ]
So, RPA=QPB
Hence, RPAQPB

997864_1060884_ans_10a22522700341a7aca5d90bb4944061.png

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