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Standard XIII

Physics

Image Shift in a Glass Slab

Rays from a l...

Question

Rays from a lens are converging toward a point $P$ as shown in figure. How much thick glass plate having refractive index $1.6$ must be located between the lens and point $P$ , so that the image will be formed at $P$ ’?

0.8 c m

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1.6 c m

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0.8 c m

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2.4 c m

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Solution

The correct option is A $0.8 c m$
The glass slab will produce a shift in the image parallel to the principal axis.

Shift produced by the glass slab $= t h i c k n e s s \times \frac{n_{1}}{n_{2}}$

i.e $0.3 = t h i c k n e s s \times \frac{1}{1.6}$

i.e thickness of the slab $= 0.8 c m$

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Figure

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Rays from a lens are converging toward a point P as shown in figure. How much thick glass plate having refractive index 1.6 must be located between the lens and point P, so that the image will be formed at P’?

The correct option is A 0.8 cmThe glass slab will produce a shift in the image parallel to the principal axis. Shift produced by the glass slab =thickness×n1n2 i.e 0.3=thickness×11.6 i.e thickness of the slab =0.8 cm

Rays from a lens are converging toward a point $P$ as shown in figure. How much thick glass plate having refractive index $1.6$ must be located between the lens and point $P$ , so that the image will be formed at $P$ ’?

The correct option is A $0.8 c m$
The glass slab will produce a shift in the image parallel to the principal axis.

Shift produced by the glass slab $= t h i c k n e s s \times \frac{n_{1}}{n_{2}}$

i.e $0.3 = t h i c k n e s s \times \frac{1}{1.6}$

i.e thickness of the slab $= 0.8 c m$