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Standard XII

Physics

f-R Relationship

Rays from a l...

Question

Rays from a lens are converging towards a point $P$ , as shown in figure, How much thick glass plate having refractive index $1.6$ must be located between the lens and point $P$ , so that the image will be formed at $P^{'}$ ?

0.8 c m

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1.6 c m

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5 c m

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2.4 c m

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Solution

The correct option is D $0.8 c m$
Due to the insertion of glass plate, the image has to be shifted by $0.3 c m$ .
Shift produced by a glass slab of thickness $t$ and refractive index $μ$ is given by $(1 - \frac{1}{μ})$ .
So, $t [1 - \frac{1}{1.6}] = 0.3 \Rightarrow t = 0.8 c m$ .

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Figure

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Rays from a lens are converging towards a point P, as shown in figure, How much thick glass plate having refractive index 1.6 must be located between the lens and point P, so that the image will be formed at P′?

The correct option is D 0.8cmDue to the insertion of glass plate, the image has to be shifted by 0.3 cm.Shift produced by a glass slab of thickness t and refractive index μ is given by (1−1μ).So, t[1−11.6]=0.3⇒t=0.8 cm.

Rays from a lens are converging towards a point $P$ , as shown in figure, How much thick glass plate having refractive index $1.6$ must be located between the lens and point $P$ , so that the image will be formed at $P^{'}$ ?

The correct option is D $0.8 c m$
Due to the insertion of glass plate, the image has to be shifted by $0.3 c m$ .
Shift produced by a glass slab of thickness $t$ and refractive index $μ$ is given by $(1 - \frac{1}{μ})$ .
So, $t [1 - \frac{1}{1.6}] = 0.3 \Rightarrow t = 0.8 c m$ .