Rays from Sun converge at a point 15 cm in front of a concave mirror. Where should an object be placed so that size of its image is equal to the size of the object ?

15 cm in front of the mirror

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30 cm in front of the mirror

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between 15 cm and 30 cm in front of the mirror

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more than 30 cm in front of the mirror

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Solution

The correct option is D 30 cm in front of the mirror
The ray diagram illustrates that, in case of a concave mirror, the image size becomes equal to the object size when the object distance equals the radius of curvature, i.e, twice the focal length.
So, the object has to be placed at a distance of $(15 \times 2) = 30 c m$ in front of the concave mirror.

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Similar questions

Question 10
Rays from sun converge at a point 15 cm in front of a concave mirror. Where should an object be placed so that size of its image is equal to the size of the object?

(a) 15 cm in front of the mirror
(b) 30 cm in front of the mirror
(c) between 15 cm and 30 cm in front of the mirror
(d) more than 30 cm in front of the mirror

Question 10
Rays from sun converge at a point 15 cm in front of a concave mirror. Where should an object be placed so that size of its image is equal to the size of the object?

(a) 15 cm in front of the mirror
(b) 30 cm in front of the mirror
(c) between 15 cm and 30 cm in front of the mirror
(d) more than 30 cm in front of the mirror

Rays from the sun converge at a point 15 cm in front of a concave mirror. Where should an object be placed in front of this mirror so that the size of its image is equal to the size of the object?

Q. An object of length

4 c m

is placed in front of a concave mirror at a distance of

30 c m

. The focal length of mirror is

15 c m

. Where will the image form?

Question 15
An object of size 7.0 cm is placed at 27 cm in front of a concave mirror of focal length 18 cm. At what distance from the mirror should a screen be placed so that a sharp focused image can be obtained? Find the size and the nature of the image.

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