Question

Re arrange in descending order
$\frac{7}{8};\frac{2}{16};\frac{4}{8};\frac{6}{16}$

Answer 1

$\frac{7}{8};\frac{2}{16}=\frac{1}{8};\frac{4}{8};\frac{6}{16}=\frac{3}{8}$

Now, in descending order,

$\frac{7}{8}>\frac{4}{8}>\frac{3}{8}>\frac{1}{8}$

i.e., $\frac{7}{8}>\frac{4}{8}>\frac{6}{16}>\frac{2}{16}$